[20251006] BOJ / G3 / 두 직사각형 / 권혁준

Author: oncsr

khj20006/202510/06 BOJ G3 두 직사각형.md

@@ -0,0 +1,68 @@
+```cpp
+#include <bits/stdc++.h>
+using namespace std;
+using ll = long long;
+
+int T, N;
+vector<pair<ll, ll>> v;
+vector<ll> L, R;
+
+int main(){
+    cin.tie(0)->sync_with_stdio(0);
+    
+    for(cin>>T;T--;) {
+        cin>>N;
+        v = vector<pair<ll, ll>>(N);
+        for(auto &[a,b]:v) cin>>a>>b;
+        if(N == 1) {
+            cout<<"0\n";
+            continue;
+        }
+
+        sort(v.begin(), v.end());
+        
+        L = vector<ll>(N);
+        ll mx = v[0].second, mn = v[0].second;
+        for(int i=0;i<N;i++) {
+            mx = max(mx, v[i].second);
+            mn = min(mn, v[i].second);
+            L[i] = (v[i].first-v[0].first) * (mx-mn);
+        }
+        
+        R = vector<ll>(N);
+        mx = v[N-1].second, mn = v[N-1].second;
+        for(int i=N-1;i>=0;i--) {
+            mx = max(mx, v[i].second);
+            mn = min(mn, v[i].second);
+            R[i] = (v[N-1].first-v[i].first) * (mx-mn);
+        }
+
+        ll ans = 1e18;
+        for(int i=1;i<N;i++) ans = min(ans, max(L[i-1], R[i]));
+        
+        sort(v.begin(), v.end(), [](auto a, auto b) -> bool {
+            return a.second == b.second ? a.first < b.first : a.second < b.second;
+        });
+        
+        L = vector<ll>(N);
+        mx = v[0].first, mn = v[0].first;
+        for(int i=0;i<N;i++) {
+            mx = max(mx, v[i].first);
+            mn = min(mn, v[i].first);
+            L[i] = (v[i].second-v[0].second) * (mx-mn);
+        }
+
+        R = vector<ll>(N);
+        mx = v[N-1].first, mn = v[N-1].first;
+        for(int i=N-1;i>=0;i--) {
+            mx = max(mx, v[i].first);
+            mn = min(mn, v[i].first);
+            R[i] = (v[N-1].second-v[i].second) * (mx-mn);
+        }
+
+        for(int i=1;i<N;i++) ans = min(ans, max(L[i-1], R[i]));
+        cout<<ans<<'\n';
+    }
+
+}
+```