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指定漏洞时无法利用解决方法 #37

@dongyu29

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@dongyu29

替换1505行附近的代码为:
name = name.upper().replace('-', '')
converted_name = name.upper().replace('-', '
')
found = any(vuln_class.name == converted_name for vuln_class in s2_list)
if not found:
click.secho("[ERROR] 暂不支持{name}漏洞利用".format(name=name), fg="red")
exit(0)

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