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Description
书中代码如下:
#include <iostream>
#include <tuple>
template <typename TSeqCont>
struct Tail_;
template <template <typename...> class Container, typename TH, typename...TCases>
struct Tail_<Container<TH, TCases...>>
{
using type = Container<TCases...>;
};
template <typename TSeqCont>
using Tail = typename Tail_<TSeqCont>::type;
int main(){
using Cont=std::tuple<char,long,int>;
std::cout<<"tail:"<<typeid(Tail<Cont>).name()<<std::endl;
return 0;
}理论上输出应该为i,但是实际上输出为St5tupleIJliEE。
请问什么原因,如何解决
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