Result service is require WSDL file

[mmuruev]

In runtime after generation got weir error.

dummy-java-name/TestService.wsdl (No such file or directory).
	at com.sun.xml.ws.wsdl.parser.RuntimeWSDLParser.tryWithMex(RuntimeWSDLParser.java:235)
	at com.sun.xml.ws.wsdl.parser.RuntimeWSDLParser.parse(RuntimeWSDLParser.java:216)
	at com.sun.xml.ws.wsdl.parser.RuntimeWSDLParser.parse(RuntimeWSDLParser.java:179)
	at com.sun.xml.ws.wsdl.parser.RuntimeWSDLParser.parse(RuntimeWSDLParser.java:148)
	at com.sun.xml.ws.client.WSServiceDelegate.parseWSDL(WSServiceDelegate.java:336)
	at com.sun.xml.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:293)
	at com.sun.xml.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:201)
	at com.sun.xml.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:182)
	at com.sun.xml.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:178)
	at com.sun.xml.ws.spi.ProviderImpl.createServiceDelegate(ProviderImpl.java:89)
	at jakarta.xml.ws.Service.<init>(Service.java:82)
	at com.test.demo.api.generated.TestService.<init>(FCUBSAccService.java:54)

I do belive that this is happening because this section in generated code

    static {
        URL url = TestService.class.getResource("TestService.wsdl");
        if (url == null) {
            url = TestService.class.getClassLoader().getResource("TestService.wsdl");
        }
        if (url == null) {
            java.util.logging.Logger.getLogger(TestService.class.getName())
                .log(java.util.logging.Level.INFO,
                     "Can not initialize the default wsdl from {0}", "TestService.wsdl");
        }
        WSDL_LOCATION = url;
    }

Seems weird solution bring whole WSDL file into build for one link only?? (and this can be big one). Second issue since you can see its not going to look for file into resources at all. I see by error it looking in the project root dir (dummy-java-name) is project dir.
Right path will be resources/main/wsdl/TestService.wsdl