get a bigger NME result

[Nancyh-e]

sorry to bother you and thanks for release your version on github. But i have some questions about NME.
when i try to get the NME of PRNET, i got a really bigger result than the author. so i doubt i use a wrong method.
How could I get the NME result of 3D 68 points on AFLW 2000 data? I try to calculating the L2 distance between the predicted result of 3D model 68 points(from kpt.txt)and ground truth(from AFLW2000 .mat file of pt3d_68) , and then use the result to /d(d is the bounding box of 68 kpts, it is about 180)/68(the number of points) according to NME expression.The method to get d is llen = sqrt((maxx - minx) * (maxy - miny)); or d = np.sqrt((maxx - minx) ** 2 + (maxy - miny) ** 2).(don't know choose which one)
But the 2 methods to get d is incorrect after i get the final result of NME.I doubt it is a mistake,and I don't know how to calculate.The result is similar to 0.33 or so ,not similar to the paper result like 0.0326.
Many thanks for taking your time to read it, i am really looking forward to your reply! ! !Have a great day! Thanks again!:）and my mailbox is CYNh_e@126.com.

[reshow]

Sorry to reply so late.
I use the first one to calculate NME.
The y-axis direction of the processed position map is not the same as the initial .mat file.
(I used a y=256-y in the data pre-process.)

I suggest you to plot the landmarks on the images to check it.