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1 change: 1 addition & 0 deletions 03_homework/homework_1.md
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Expand Up @@ -76,3 +76,4 @@ Please do not pick the exact same tables that I have already diagramed. For exam
- ![01_farmers_market_conceptual_model.png](./images/01_farmers_market_conceptual_model.png)
- The column names can be found in a few spots (DB Schema window in the bottom right, the Database Structure tab in the main window by expanding each table entry, at the top of the Browse Data tab in the main window)

![image](https://github.com/monzchan/SQL/assets/166637673/863d31cf-46f9-4d5e-85ff-a4a6128e3680)
33 changes: 32 additions & 1 deletion 03_homework/homework_2.md
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# SELECT
1. Write a query that returns everything in the customer table.
SELECT * FROM customer


2. Write a query that displays all of the columns and 10 rows from the customer table, sorted by customer_last_name, then customer_first_ name.
SELECT * FROM customer ORDER BY customer_last_name, customer_first_name LIMIT 10


# WHERE
1. Write a query that returns all customer purchases of product IDs 4 and 9.
2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), filtered by vendor IDs between 8 and 10 (inclusive) using either:
SELECT * FROM customer_purchases
WHERE product_id BETWEEN 4 AND 9

2. Write a query that returns all customer purchases and a new calculated column 'price'
(quantity * cost_to_customer_per_qty), filtered by vendor IDs between 8 and 10 (inclusive) using either:
1. two conditions using AND
2. one condition using BETWEEN
SELECT *, (quantity * cost_to_customer_per_qty) AS price
FROM customer_purchases
WHERE vendor_id BETWEEN 8 AND 10


# CASE
1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. Using the product table, write a query that outputs the `product_id` and `product_name` columns and add a column called `prod_qty_type_condensed` that displays the word “unit” if the `product_qty_type` is “unit,” and otherwise displays the word “bulk.”
SELECT product_id, product_name,
CASE WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product


2. We want to flag all of the different types of pepper products that are sold at the market. Add a column to the previous query called `pepper_flag` that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0.
SELECT *,
CASE WHEN product_name LIKE '%pepper%' THEN 1 ELSE 0 END AS pepper_flag
FROM product



# JOIN
1. Write a query that `INNER JOIN`s the `vendor` table to the `vendor_booth_assignments` table on the `vendor_id` field they both have in common, and sorts the result by `vendor_name`, then `market_date`.
SELECT *
FROM vendor
JOIN vendor_booth_assignments
ON vendor.vendor_id=vendor_booth_assignments.vendor_id
ORDER BY vendor_name, market_date


34 changes: 34 additions & 0 deletions 03_homework/homework_3.md
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# AGGREGATE
1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per `vendor_id`.

SELECT vendor_id, COUNT(booth_number)
FROM vendor_booth_assignments
GROUP BY vendor_id

2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list of customers for them to give stickers to, sorted by last name, then first name.
**HINT**: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword.

SELECT c.customer_id, c.customer_first_name, c.customer_last_name, sum(cp.quantity* cp.cost_to_customer_per_qty) AS totalpurchase
FROM customer c
INNER JOIN customer_purchases cp
ON c.customer_id = cp.customer_id
GROUP BY customer_last_name, customer_first_name
HAVING totalpurchase>2000
ORDER BY customer_last_name, customer_first_name





# Temp Table
1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
**HINT**: This is two total queries -- first create the table from the original, then insert the new 10th vendor. When inserting the new vendor, you need to appropriately align the columns to be inserted (there are five columns to be inserted, I've given you the details, but not the syntax)

To insert the new row use VALUES, specifying the value you want for each column:
`VALUES(col1,col2,col3,col4,col5)`

DROP TABLE IF EXISTS temp.new_vendor;
CREATE TEMP TABLE temp.new_vendor AS
SELECT * FROM vendor;
INSERT INTO temp.new_vendor VALUES (10, 'Thomass Superfood', 'Fresh Focused', 'Rosenthal', 'Thomas');




# Date
1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
**HINT**: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month and year are!
SELECT customer_id, STRFTIME('%Y', market_date), STRFTIME('%m', market_date)
FROM customer_purchases

2. Using the previous query as a base, determine how much money each customer spent in April 2019. Remember that money spent is `quantity*cost_to_customer_per_qty`.
**HINTS**: you will need to AGGREGATE, GROUP BY, and filter...but remember, STRFTIME returns a STRING for your WHERE statement!!


SELECT customer_id, STRFTIME('%Y', market_date) AS market_year, STRFTIME('%m', market_date) AS market_month
, SUM(quantity * cost_to_customer_per_qty) AS totalpurchase
FROM customer_purchases
GROUP BY market_year, market_month, customer_id
HAVING market_year LIKE '2019' AND market_month LIKE '04'